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IgorC [24]
3 years ago
11

The t value for a 99% confidence interval estimation based upon a sample of size 10 is

Mathematics
1 answer:
Aliun [14]3 years ago
7 0
Answer:
For a sample size of 10, the t-value is about 3.25 (from tables) at a 99% confidence interval.

Explanation:
When the standard deviation for the population is not known, the confidence interval estimate for the population mean is performed with the Student's t-distribution.
The confidence interval for the mean is calculated as
(\Bar{x}- t\frac{s}{\sqrt{n}} , \, \Bar{x}+ t\frac{s}{\sqrt{n}}
where
 \Bar{x} = sample mean,
s = sample standard deviation,
t = t-value (provided in tables),
n =  sample size.

When reading the t-value, (n-1) is called the df or degrees of freedom.

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ANSWER:

the answer 130

Step-by-step explanation:

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4 years ago
if the balance at the end of eight years on an investment of $230 that has been invested at the rate of 3% is $285.2 how much wa
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3 years ago
To find the percent of the yellow tint in the new mixture?
Ivanshal [37]
1)We need to know the amount of yellow tint in the old mixture.

amount of yellow tint=30% of 40 liters
30%=30/100=0.3

Amount of yellow tint=0.3(40 liters)=12 liters.

2)We need to find the amount of yellow tint in the new mixture.

amount of yellow tint in the new mixture=12 liters + 9 liters=21 liters.

3) we calculate the amount of the new mixture:
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Answer: The percent of yellow tint in the new mixture is 42.9%. 

note: if this answer is not correct you can try it  with 42.8%
6 0
3 years ago
Simplify.
steposvetlana [31]
I hope this helps you



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4 0
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Read 2 more answers
Adam and his dad share the cost of the meal in the ratio of 2:3.
mel-nik [20]
Given that the meal cost is shared by Adam and his dad is in the ratio 2:3 respectively, and the amount of money paid by Adam's dad was 52.20, thus the
total cost of meal will be:
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5/3*52.20
=87
Thus we conclude that the total cost of food was 87 pounds

7 0
4 years ago
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