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3 years ago

The t value for a 99% confidence interval estimation based upon a sample of size 10 is

1 answer:

7 0

Answer:
For a sample size of 10, the t-value is about 3.25 (from tables) at a 99% confidence interval.

Explanation:
When the standard deviation for the population is not known, the confidence interval estimate for the population mean is performed with the Student's t-distribution.
The confidence interval for the mean is calculated as
$(\Bar{x}- t\frac{s}{\sqrt{n}} , \, \Bar{x}+ t\frac{s}{\sqrt{n}}$
where
$\Bar{x}$ = sample mean,
s = sample standard deviation,
t = t-value (provided in tables),
n = sample size.

When reading the t-value, (n-1) is called the df or degrees of freedom.

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4 years ago

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3 years ago

A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the

devlian [24]

Answer:

The probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be $\frac{1}{5}$ .

Step-by-step explanation:

We have 10 members out of which one is Harry, we need to choose one of the 10 members as President, one to be as secretary out of the remaining 9, one as the treasurer of the remaining 8 members.

We want harry to be as either as secretary or as treasurer. so we will consider both the cases

Probability is given by = No of favorable outcomes/ Total no of outcomes

(1) Harry as secretary : If harry is to be chosen as secretary then he can't be a president or he cant be a Treasurer

As president = $\frac{1}{10}$

Not as president = $1 - \frac{1}{10}$ = $\frac{9}{10}$

Now he is selected for the secretary so he can't be selected as treasurer.

Not as treasurer = 1

Probability for chosen as secretary = $\frac{9}{10}*\frac{1}{9}*1$ = $\frac{1}{10}$

(2) Harry as treasurer : If harry is to be chosen as the treasurer so he can't be chosen as a President or as a Secretary.

Probability for not chosen as president = $\frac{9}{10}$

Probability for not chosen as secretary = $1-\frac{1}{9} = \frac{8}{9}$

Probability to be chosen as treasurer = $\frac{1}{8}$

Probability to be chosen as Treasurer = $\frac{9}{10}*\frac{8}{9}*\frac{1}{8}$ = $\frac{1}{10}$

Total probability for Harry to be chosen as either secretary or as treasurer will be = P(Secretary) +P(Treasurer)

= $\frac{1}{10} +\frac{1}{10} = \frac{1}{5}$

Therefore the probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be $\frac{1}{5}$ .

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3 years ago

List the integers that satisfy both of these inequalities 2x+9<0 x>-12 put the answers on one line

lbvjy [14]

Answer:

Step-by-step explanation:

Given the inequality expressions

2x+9<0 and x>-12

2x+9<0

2x< 0-9

2x < -9

x < -9/2

x < -4.5

Since x >-12

-12 < x

Combining both inequalities

-12 <x < 4.5

<em>The integers between the intervals are -11, -10, -9, -8, -7, -6 and -5 </em>

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3 years ago

1/2(12•x)=276 solve for x

tatiyna

The answer is 11.5 (please mark me as brainliest if true)

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3 years ago

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