Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
Simplify: 49 - 4 x 49 ÷ 7 21 34 36
2 answers:
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Answer:
So the answer for this case would be n=62 rounded up to the nearest integer
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean
represent the population standard deviation
n represent the sample size (variable of interest)
Confidence =95% or 0.95
The margin of error is given by this formula:
(1)
And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:
(2)
The critical value for 95% of confidence interval is provided, , replacing into formula (2) we got:
So the answer for this case would be n=62 rounded up to the nearest integer