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3 years ago

Which of the following sets of data would you likely represent with a square matrix?

Mathematics

2 answers:

Nookie1986 [14]3 years ago

8 0

Answer:

Step-by-step explanation:

E2020

n200080 [17]3 years ago

7 0

Answer:

B) A racquetball club has a tournament where each member plays every other member and represents the scores in a matrix.

Step-by-step explanation:

A square matrix is where the number of rows is equal to the number of columns like order 2x2, 3x3, 4x4, 5x5 etc.

Given options are:-

A) A shoe salesperson wants to use an augmented matrix to represent the quantity of children’s shoes and adult shoes sold at his store for two days.

It is 2x2 times 2x1 = 2x1 matrix.

B) A racquetball club has a tournament where each member plays every other member and represents the scores in a matrix.

It is 6x1 times 1x6 = 6x6 matrix.

C) A student wants to write a coefficient matrix representing a linear system with two equations and three unknowns.

It is 2x3 times 3x1 = 2x1 matrix

D) A teacher wants to write an augmented matrix representing a linear system with four equations and four unknowns.

It is 4x4 times 4x1 = 4x1 matrix.

Hence option B is correct.

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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

What is a solution I forgot the inequality M > 13/6

o-na [289]

The solution can be anything bigger than 13/6.

For example: 3, 4, 5, 6...ect

7 0

3 years ago

What is the exponent of x in in the expression -4x^3y^2 + 6

liberstina [14]

Answer:

Step-by-step explanation:

- 4x³y² + 6

the x is raised to the power of 3 , that is exponent of x is 3

4 0

2 years ago

How do I solve for the solution??<br>y = 3x +2<br>y = x + 1

Elis [28]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−1/2,1/2)

Equation Form:

x=−1/2,y=1/2

Step-by-step explanation:

7 0

3 years ago

Please help.

serious [3.7K]

The number of throws that the player make X follows binomial distribution.

The probability that the player makes x throws out of eleven throws is

$P(X=x)=C(x,11)0.5^x(0.5)^{11-x}=C(x,11)0.5^{11}$

The probability that the player makes at most nine out of eleven free throws

$\sum_{x=0}^9C(x,11)0.5^{11}=1-\sum_{x=10}^{11}C(x,11)0.5^{11}\\ =1-C(10,11)0.5^{11}-C(11,11)0.5^{11}=1-\frac{12}{2^{11}} \\ =1-\frac{3}{512} =\frac{509}{512}$

Correct choice is (B).

8 0

3 years ago