3 years ago

Write the standard equation for the circle with center (–2, 5) that passes through (1, 9).

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

All given options are incorrect .. As no one is the equation of a circle

mr_godi [17]3 years ago

6 0

Hello,

Answer D:

1) we must find the radius:

r²=(1-(-2))²+(9-5à²=3²+4²=9+16=25=5²

The circle's equation is
(x-(-2))²+(y-5)²=25
or (x+2)²+(y-5)²=25

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X and y simplifying problem. Please explain how to do thiese. I will gove 15 points

Strike441 [17]

$\dfrac 56 x + \dfrac25 y - \dfrac14 x + \dfrac3{10} y$

First, combine like terms:

$\left(\dfrac 56 - \dfrac14\right) x + \left(\dfrac25 + \dfrac3{10}\right)y$

Now just simplify the coefficients of x and y. We do this by converting each pair of fractions to ones with a common denominator. Then we can combine them easily.

$\dfrac56 - \dfrac14 = \dfrac56\cdot\dfrac22 - \dfrac14\cdot\dfrac33 = \dfrac{5\cdot2}{6\cdot2} - \dfrac{1\cdot3}{4\cdot3} = \dfrac{10}{12} - \dfrac3{12} = \dfrac{10-3}{12} = \dfrac7{12}$

$\dfrac25 + \dfrac3{10} = \dfrac25\cdot\dfrac22 + \dfrac3{10} = \dfrac{2\cdot2}{5\cdot2} + \dfrac3{10} = \dfrac4{10} + \dfrac3{10} = \dfrac{4+3}{10} = \dfrac7{10}$