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Nataly [62]
3 years ago
13

Find ∫^[infinity]_-[infinity] x/(1+x^2)^2 dx.

Mathematics
1 answer:
son4ous [18]3 years ago
3 0

Answer:

Step-by-step explanation:

integral(x/(1+x^2)^2)dx

=(1/2)integral(2x/(1+x^2)^2)dx

=(1/2)[-1/(1+x^2)] +c

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Use the box method to distribute and simplify (-5x-2)(-2x^2+6x).
Mkey [24]

Answer:

10x^{3} - 26x^{2} - 12x

Step-by-step explanation:

1)  Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

10x^{3} - 30x^{2} + 4x^{2} -12x

2)  Collect like terms.

10x^{3} + (-30x^{2} +4x^{2} )-12x

3) Simplify.

10x^{3} - 26x^{2} -12x

Therefor, the answer is, 10x^3 - 26x^2 - 12x.

3 0
3 years ago
How do you solve and simplify
DedPeter [7]
F(x) = 1/(x+2)   & g(x) = x/(x-3)


(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)

7 0
3 years ago
What is the momentum of 200kg portable if it travels 50 meters in 5seconds
kvasek [131]
Momentum  = mass * velocity

50 meters in 5 seconds = 50/5  = 10 m / second

Required momentum  = 200*10  = 2,000 

I cant remember how to write the units for this.
5 0
3 years ago
Complete the paragraph proof. We are given that ∠B ≅ ∠C. Assume segment AB is not congruent to . If AB > AC, then m∠C > m∠
Lorico [155]

Given that ∠B ≅ ∠C.

to prove that the sides AB = AC

This can be done by the method of contradiction.  

If possible let AB \neq=AC

Then either AB>AC or AB<AC

Case i:  If AB>AC, then by triangle axiom, Angle C > angle B.

But since angle C = angle B, we get AB cannot be greater than AC

Case ii:  If AB<AC, then by triangle axiom, Angle C < angle B.

But since angle C = angle B, we get AB cannot be less than AC

Conclusion:

Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC

Hence if angle B = angle C it follows that

AB = AC, and AB ≅ AC.

6 0
3 years ago
Read 2 more answers
5/9 rounded to the nearest half?
Archy [21]

0.6.

5/9 = 0.5555555... which rounds to 0.6

6 0
3 years ago
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