3 years ago

Find ∫^[infinity]_-[infinity] x/(1+x^2)^2 dx.

1 answer:

3 0

Answer:

Step-by-step explanation:

integral(x/(1+x^2)^2)dx

=(1/2)integral(2x/(1+x^2)^2)dx

=(1/2)[-1/(1+x^2)] +c

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