Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 8
Putting x=1.5 in Eqn 1
Dividing both sides by 8
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
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What form do you need it in?
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}
The rule for a rotation by 180° about the origin is (x,y) -->(−x,−y)
So A(-3, 2) to A'(3, -2)
Answer:
A'(3, -2)
3/8 times 8/3 = 1
Answer=8/3
