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2 years ago

What is 36/4 as a mixed number

Mathematics

1 answer:

Yuliya22 [10]2 years ago

3 0

It cannot be expressed as a mixed fraction. Dividing 36 by 4 gives 9 which is a whole number.

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Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog

nydimaria [60]

Answer:

Answer is given below.

Step-by-step explanation:

Number of people, n = 400

Number of people who agree with the statement is 112.

Number of people who disagree with the statement is 288

Using Stat Key, follow the steps below to obtain the 95% confidence interval for the

proportion of the population to agree with the statement.

1) Open

2) Click on CI for single proportion.

3) Click Edit data key.

4) Enter 112 in count text box.

5) Enter 400 in Sample size text box.

6) Click two-tail.

7) Click Generate 1000 samples key.

Output: (See Image).

Original Sample

Count SampleSize Proportion

112 400 0.280

Bootstrap Sample

Count SampleSize Proportion

128 400 0.320

From the above dot plot , it can be observed that the standard error shows top right corner.

Thus the standard error is 0.022.

From the output, the 95% confidence interval is 0.2371 to 0.325

4 0

2 years ago

A survey of a group of seventh graders and a group of teachers at a local middle school asked how many siblings they each have.

wolverine [178]

Answer:

The closest statement is B. The median for the students is 2 and the median for the teachers is 3.

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of students = 20

Siblings 0 1 2 3 4 5 6 7 8 9

Students 2 4 7 5 2 0 0 0 0 0

Number of teachers = 20

Siblings 0 1 2 3 4 5 6 7 8 9

Teachers 1 3 2 4 5 3 1 0 1 0

2. Which statement compares the medians of the data?

Let's recall that the median of a set of data (students or teachers) is the middlemost number in the set. The median is also the number that is halfway into the set. To find the median, the data should be arranged in order from least to greatest. If there is an even number of items in the data set, then the median is found by taking the mean (average) of the two middlemost numbers, the 10th and 11th values from left to right for the students and teachers.

Upon saying that, let's meet the median of the data sets provided:

Median for the students = 10th and 11th values/2

Median for the students = (2 + 2)/2 = 2

Median for the teachers = 10th and 11th values/2

Median for the teachers = (3 +4)/2 = 3.5

The closest statement is B. The median for the students is 2 and the median for the teachers is 3.

4 0

3 years ago

Read 2 more answers

PLS Help me in question 34 and 35

attashe74 [19]

34- 6, 12, 18, 24, 30, 36
35- 15, 30, 45, 60, 75, 90

3 0

2 years ago

WILL GIVE BRAINLIEST

Elza [17]

Answer:

99 people is the answer

Step-by-step explanation:

.48 x 208 = 99

7 0

2 years ago

Read 2 more answers

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

2 years ago