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lbvjy [14]
3 years ago
5

the table below gives the average cost, x (to the nearest hundred) of tuition and fees, y, at a four year college

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0
22
476352nbvo
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Given z3 = 3 + StartRoot 3 EndRoot ii, which letter represents z?
Vlada [557]

Answer:

It is A

Step-by-step explanation:

Got it right on the test :)

4 0
2 years ago
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Please!!!!!!!
kicyunya [14]

Answer:

B.

Step-by-step explanation:

4 0
2 years ago
What is x?
Nadya [2.5K]

Answer:

Option 3) 24 is right.

Step-by-step explanation:

Given in the picture is a triangle LMN. sides are MN = 12, LN = 21 and LM = x cm

Also MO is the angle bisector of angle M.

By applying angle bisector theorem for triangles we get

LM/MN = LO/NO

i.e. x/12 = 14/7

Simplify to get x = 24

Hence option 3 is right

Verify:

Check whether angle bisector theorem is true.

The proportion LM/MN =24/12 = 2

The proportion LO/NO  =14/7 =2

Both are equal and hence verified

8 0
3 years ago
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How to find 62%of $400​
gayaneshka [121]

Answer:

248

Step-by-step explanation:

Solution for What is 400 percent of 62:

400 percent *62 =

(400:100)*62 =

(400*62):100 =

24800:100 = 248

Now we have: 400 percent of 62 = 248

Question: What is 400 percent of 62?

Percentage solution with steps:

Step 1: Our output value is 62.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$62=100\%.

Step 4: Similarly, x=400\%.

Step 5: This results in a pair of simple equations:

62=100\%(1).

x=400\%(2).

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

\frac{62}{x}=\frac{100\%}{400\%}

Step 7: Again, the reciprocal of both sides gives

\frac{x}{62}=\frac{400}{100}

\Rightarrow x=248

Therefore, 400 of 62 is 248

5 0
3 years ago
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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

4 0
2 years ago
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