Answer:
About 1.85 seconds and 13.15 seconds.
Step-by-step explanation:
The height (in feet) of the rocket <em>t</em> seconds after launch is given by the equation:

And we want to determine how many seconds after launch will be rocket be 390 feet above the ground.
Thus, let <em>h</em> = 390 and solve for <em>t: </em>
<em />
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Isolate:

Simplify:

We can use the quadratic formula:

In this case, <em>a</em> = 8, <em>b</em> = -120, and <em>c</em> = 195. Hence:

Evaluate:

Simplify:

Thus, our two solutions are:

Hence, the rocket will be 390 feet above the ground after about 1.85 seconds and again after about 13.15 seconds.
Answer:
43 46 34 98 78 67
Step-by-step explanation:
Answer:
36.3
Step-by-step explanation:
145.2/4 = length of each side
145.2/4 = 36.3
17,157 is the answer to your question...I can't really put down work with texting