A Trapezoid needs to have one pair of sides parallel.
Two of the points already plotted have the same Y value ( 3)
So the 4th dot, should have the same Y value as the first dot, which is 1.
The 4th dot should be plotted at C (5,1)
Answer:
it is the answer. let me do research and I will get answer
This is describing how your graph should be numbered. If I understand it, it is saying that your y-axis should be numbered by 2s while your x-axis should be numbered by 1s.
Below, I have attached an example graph that may help you understand.
Statements 1,2,4, and 5 are true
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
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These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
