The tangent vector to r(<em>t</em>) at any <em>t</em> in the domain is

At <em>t</em> = π/6, the tanget vector is

To get the unit tangent, normalize this vector by dividing it by its magnitude:

So the unit tangent at the given point is

Answer:
Its n = 45
Step-by-step explanation:
Multiply both sides of the equation by 3 .
3 ⋅
= 3 ⋅ 14
Simplify both sides of the equation.
n = 45
I hope this helps
if you could, feel free to mark me Brainliest it would be much appreciated :D
Answer:
y=(1/3)x+5
Step-by-step explanation:
Slope-intercept: y=mx+b
m=((y2-y1)/(x2-x1)) = (6-4)/(3+3)= 2/6= (1/3)
y=(1/3)x+b
plug in one of the points (3,6)
6=(1/3)(3)+b
6=1+b 5=b
Answer:
Hello,
Step-by-step explanation:
Roots are -2 and 4
y=k*(x+2)(x-4)
Vertex = (1,-9) is a point of the parabola
-9=k*(1+2)(1-4) ==> k=1
Equation of the parabola is y=(x+2)(x-4)
But you don' t have given the graphs !!!!