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Marina86 [1]
2 years ago
12

(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3) Enter the answer in science notification

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
7 0

Multiply the coefficients and the powers of 10 with each other:

(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})

The numeric part simply yields

3.8\times2.37 = 9.006

As for the powers of 10, you have to add the exponents, using the rule

a^b \times a^c = a^{b+c}

So, we have

10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}

So, the final answer is

9.006\times 10^{-9}

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Answer:  The required number of ways is 25401600.

Step-by-step explanation:  Given that seven men and seven women line up at a checkout counter in a store.

We are to find the number of ways in which they can line up, if the first person in line is a man , and the people in line alternate man, woman, man, woman and so on.

Since the first person is a man, so

for first position, we have 7 options.

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That is, we have 7 options for the second position.

Similarly, for 3rd and 4th positions, we have 6 options for each, and so on.

Therefore, the number of ways in which the 14 persons can line up is

n=7\times7\times6\times6\times5\times5\times4\times4\times3\times3\times2\times2\times1\times1=7!\times7!=5040\times5040=25401600.

Thus, the required number of ways is 25401600.

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