Answer:
The required P value is 0.0901.
The critical value for the test statistic is 1.645.
Step-by-step explanation:
Consider the provided information.
The test statistic of z=1.34 is obtained when testing the claim that p> 0.1
It is given given that z=1.34 as the claim has greater than inequality so it is a right tailed test.
Part (A) P-value
![P\ value=1-P(Z\leq z)\\P\ value=1-P(Z\leq 1.34)](https://tex.z-dn.net/?f=P%5C%20value%3D1-P%28Z%5Cleq%20z%29%5C%5CP%5C%20value%3D1-P%28Z%5Cleq%201.34%29)
From the Standard normal distribution table
.
Therefore,
![P\ value=1-0.9099=0.0901](https://tex.z-dn.net/?f=P%5C%20value%3D1-0.9099%3D0.0901)
Hence, the required P value is 0.0901.
Part (B) The critical value(s) is/are z=
It is given that the significance level is α=0.05
Using standard z value table we get the critical value for the test statistic is 1.645.
Hence, the critical value for the test statistic is 1.645.
Answer: ![(1,-\frac{3}{2})](https://tex.z-dn.net/?f=%281%2C-%5Cfrac%7B3%7D%7B2%7D%29)
Step-by-step explanation:
To find the midpoint, you use the formula
.
The points are (-2,-1) and (4,-2).
[add]
[divide]
![midpoint=(1 ,\frac{-3}{2} )](https://tex.z-dn.net/?f=midpoint%3D%281%20%2C%5Cfrac%7B-3%7D%7B2%7D%20%29)
Now, we know the midpoint is
.
Answer:
this answer requires that you do a little solving to find all the dimensions we need for the volume.
We know that H (height) = 2m
Diameter = 5 x height, so
Diameter = 5 x 2m = 10m
If you have the formula for finding the volume of a cylinder, it is basically the area of the circular base x cylinder height. You may know already that the area of a circle is (pi) x radius2
So this will be 2 (the height) x (pi) x r2
As we just figured out, the DIAMETER is 10, so the radius is half the diameter = 5.
This brings our volume to 2 x (pi) x 52
= 2 x (pi) x 25
2x25 = 50, so we have 50 x (pi).
Pi = 3.14
50 x 3.14 = 157
And don't forget your units = 157 m3
It is fine that you did not include the measure of angle XYZ in your posting.
This question is testing your knowledge of the four types of transformations.
1) Translations - an item is "slid" to a new location.
2) Reflections - an item is "flipped" (usually over the x-axis or y-axis)
3) Rotations - an item is rotated, usually around the origin (the point (0,0) is the center of most rotations, especially in high school math).
4) Dilations - an item is enlarged or reduced by a certain ratio.
It the first three, the image after the transformation is congruent to the pre-image. It has the same size and shape. It is simply flipped, rotated, slid...
But... in the fourth, dilation, the image now has a different size. It is still, however the same shape.
In geometry terms, after the first three transformations, the image is still "congruent" to the pre-image. After dilation, the image is "similar" but not "congruent."
So... all that to say that when you rotate an angle around the origin, the measure of the angle doesn't change.
So the first choice is correct. The measure of the image of the angle is the same as the measure of the angle.
<span>m∠X’Y’Z’ = m∠XYZ
</span>
If im not wrong since the scale factor from A to B is 1:4, that means if you multiply 8 x 4
You will get 32, which is the size of B. Hope this helps!