Answer:
E and F but read below.
Step-by-step explanation:
I'm reading the legs as 6 and 6 so the triangle is at least isosceles.
The question is, is it also a right angle? If it is, then the Hypotenuse is incorrectly rounded. When you calculate the hypotenuse, it comes to 8.485 which should be rounded to 8.5
Regardless of that, I think the answer is intended to by a right triangle, but don't be surprised if your marker does not agree.
Answer:
6
Step-by-step explanation:
Answer:
The area of circle with radius half of original circle is 7 π cm² .
Step-by-step explanation:
Given as :
The Area of original circle = 28 π square centimeter
Let The radius of original circle = R
Let The area of circle with radius half of original circle = A square centimeters
Let The radius of circle with radius half of original circle = R'
Now, According to question
∵ Area of original circle = π × radius²
So, 28 π cm² = π × R²
Or, R² = 
Or, R² = 28 cm²
∴ R =
cm
i.e R = 2
cm
So, The radius of original circle = R = 2
cm
<u>Again</u>
∵ The radius of circle with radius half of original circle = R'
So, R' = 
i.e R' = 
∴ R' =
cm
So, The area of circle with radius half of original circle = π × R'²
i.e A = π × R'²
Or, A = π ×(
) ²
or, A = π × 7
So, The area of circle with radius half of original circle = 7 π cm²
Hence The area of circle with radius half of original circle is 7 π cm² . Answer
Ok, good job for posting the answer