Answer:
(4.29×10¹⁵)⋅(1.96×10⁻⁴) = 8.40 × 10¹¹, has three significant digits.
Explanation:
To solve: (4.29×10¹⁵)⋅(1.96×10⁻⁴)
According to the product rule of exponents, when exponents having the same base are multiplied, the base is kept the same and the powers are added.
Therefore,
(4.29×10¹⁵)⋅(1.96×10⁻⁴) = (4.29 × 1.96) · 10⁽¹⁵⁻⁴⁾ = 8.40 × 10¹¹
<u>The number, 8.40 × 10¹¹ has three significant digits.</u>
Answer:
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Al = 1×4 = 4
- Number of atoms in C = 1×3 = 3
- Number of atoms in H = 12×2 = 24
- Number of atoms in O = 12×1 = 12
<em>In product side of equation :-</em>
- Number of atoms in C = 3×1 = 3
- Number of atoms in H = (3×4) + 4(1×3) = 24
- Number of atoms in Al = 4×1 = 4
- Number of atoms in O = 4(1×3) = 12
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
It’s some apps that come in handy for this sorry if I didn’t help
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
<span>Henry divides 1.060 g by 1.0 mL to find the density of his water sample.
</span>He should include THREE significant figures in the density value that hereports.