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Bezzdna [24]
3 years ago
5

After spraying water on a waxed surface, a student notices that the water beads up to form many individual drops rather than bei

ng spread out evenly across the surface. What property of water causes it to bead up like this? A. the high boiling point of water B. the strong adhesion to other substances C. the high density of liquid water D. the ability to dissolve many other substances E. the strong cohesion between water molecules
Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
8 0

The best answer would be:

E. The strong cohesion between water molecules.

Cohesion is the strong attraction between molecules of the same kind. Water has this property because of hydrogen. Hydrogen form strong bonds with each other which keep water molecules intact. When sprayed on a waxed surface they tend to bead because hydrogen bonds are more attracted to themselves, rather than the wax surface.

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If a substance cannot be broken down chemically into a simpler substance what is it
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Answer: An Element

Explanation:

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6 0
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An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
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<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

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2 years ago
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To solve such this we must know the concept of chemical reaction and dehydration reaction. Therefore, dehydration means to remove water from a compound.

<h3>What is chemical reaction? </h3>

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