The molecule of sulfur dioxide has two pi and two sigma bonds and one lone pair of electrons.
<h3>What is lone pair?</h3>
- A lone pair, also known as an unshared pair or a non-bonding pair, is an unshared pair of valence electrons that are not shared with another atom in a covalent connection in chemistry.
- Atom's outermost electron shell contains lone pairs. The Lewis structure can be used to locate them.
- Due to the high electric charge of a lone pair, which results in strong electron repulsion, the bond angle between the bonding pair of electrons reduces.
- They participate in the creation of a dative relationship as well.
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5. Eubacteria
6. Plantae
7. Animalia
8. Protist (technically not a kingdom)
9. Archaebacteria
10. Fungi
Evaporation, condensation, and precipitation are all parts of the water cycle. So the answer would have to be the water cycle.
<span>You are given the
mass of hydrate which is 10.24g and the mass of anhydrate which is 8.74g. Hydrate
means that it contains water and anhydrate means the substance has lost water
during the process. So you just subtract them, 10.24g – 8.74g = 1.5g of water
is lost. Percent hydration is equal to one subtracted to the mass of anhydrate
divided by the mass of hydrate multiplied by 100. So we have, [1-(8.74g/10.24g)]
*100 = 14.65% or 15%. Your answers are correct.</span>
Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction
2C2H2 + 5O2 → 4CO2 + 2H2O
(2 mole) (4 mole)
From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2
Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g
Thus, <span>114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene</span>
