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saveliy_v [14]
4 years ago
9

Simplify the imaginary number sqr -12

Mathematics
1 answer:
Anastaziya [24]4 years ago
8 0

Answer:

\sqrt{-12} = i\sqrt{12} = i\sqrt{4\cdot 3} = 2i\sqrt{3}

Step-by-step explanation:

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Find the area of equilateral triangle of side 4 cm.​
ipn [44]

Answer:6.928

Step-by-step explanation: formula A=√ 3*(side^2/4)

4 0
4 years ago
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The following information is available for Trinkle Company for the month of June:
irinina [24]

True Cash Balance As on June 30  is mathematically given as $ 52588

This is further explained below.

<h3>What is the true cash balance?</h3>

As of the Bank Statement dated June 30th, the Unadjusted Balance A = $53,382.

Deposit in Transit June B = $2,545.

Outstanding Check June 30 C = $3,339

Generally, the equation for the true cash balance is mathematically given as

cash balance = A-(C-B)

Therefore

cash balance= 53,382-(3,339-2,545.)

cash balance= 52588

In conclusion, True Cash Balance As on June 30 = $ 52588

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7 0
1 year ago
Prove diagonals of a rhombus are perpendicular
Lisa [10]

Answer:

A rhombus is a parallelogram with four congruent sides.

So, all sides of rhombus ABCD are congruent.

i.e, \overline{JM} \cong \overline{JK} \cong \overline{KL}\cong \overline{LM}

Also, we know that the diagonals of a parallelogram bisect each other.  

Since a rhombus is a parallelogram.

By property of rhombus , if point N is the intersection of the diagonals as shown in the figure, then

\overline{MN} \cong \overline{NK}         .....[1]

\overline{JN} \cong \overline{NL}

In ΔJNM and ΔJNK

\overline{MN} \cong \overline{NK}     [side]    [by (1)]

\overline{JM} \cong \overline{JK}     [side]          [Given]

By reflexive property states that a segment is congruent to itself:

\overline{JN} \cong \overline{JN}   [Side]                 [Reflexive Property]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

then by SSS congruence,

\triangle JNM \cong \triangle JNK

By CPCT [Corresponding Part of congruent triangles are congruent]

Since, JNM and JNK are corresponding angles therefore,

\angle JNM \cong JNK

Linear pair theorem states that two angles that form a linear pair are supplementary.

By linear pair theorem, JNM and JNK are supplementary

this mean:

m\angle JNM +m\angle JNK =180^{\circ}

Since, the angles are congruent i.e, \angle JNM \cong JNK

so;

m\angle JNK +m\angle JNK =180^{\circ}

or

m\angle JNK +m\angle JNK =180^{\circ}

2m\angle JNK=180^{\circ}

Simplify:

m\angle JNK =90^{\circ}

also; m\angle JNM =90^{\circ}

therefore, the diagonals of JKLM are perpendicular to each other i,e \overline{JL} \perp \overline{MK}


4 0
3 years ago
1. Matthew took a quiz with 20 questions. If he answered 16 of them correctly, what percent
mr Goodwill [35]

Answer:

80%

Step-by-step explanation:

The fraction that he got correct is

16/20

To get a percent we need out of 100

Multiply by 5/5

16/20 *5/5 = 80/100

80%

6 0
3 years ago
Identify a pattern by making a table of the inputs and outputs.
-BARSIC- [3]

it wants you to make a table of the inputs and out puts, and what is the pattern that is happening. like is it a constant increase/decrease and things like that. i'll help you on the table...

x | y

1 | 5

2 | 4

3 | 3

4 | 2

(i am not sure what that 40 is at the end, but You get the point)

now all you have to do is identify the sequence or pattern you see here


3 0
4 years ago
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