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Ahat [919]
3 years ago
6

Calculate S (sub) 4 for the sequence defined by {a(sub)n}={19-4n}

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0
Yup, you  are correct 
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Given the following sets:
hjlf
<h3>Answer:  10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C =  {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t,   d, h, I, p, t  }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0
2 years ago
Eric teaches ceramics in his studio.he estimates that one out of every five people who call for information about a class will s
Vlada [557]

The probability that four or fewer of the people who called will sign up for a class = 0.9805

For given question,

Eric estimates that one out of every five people who call for information about a class will sign up for the class.

Last week he receive nine calls.

We need to find the probability that four or fewer of the people who called will sign up for a class.

Total number of calls = 9

⇒ n = 9

Since one out of every five people who call for information about a class will sign up for the class.

the probability of success (p) = 1/5

                                                  = 0.2

and the probability of failure (q) = 1 - p

                                                      = 1 - 0.2

                                                      = 0.8

To find the probability that four or fewer of the people who called will sign up for a class.

So, x would take values 0, 1, 2, 3, 4

Using Binomial principal,

For x = 0,

P(x=0)= ~^9C_0(0.2)^0(0.8)^{9-0}\\\\P(x=0)=0.13422

For x = 1,

P(x=1)= ~^9C_1(0.2)^1(0.8)^{9-1}\\\\P(x=1)=0.30199

For x = 2,

P(x=2)= ~^9C_2(0.2)^2(0.8)^{9-2}\\\\P(x=2)=0.30199

For x = 3,

P(x=3)= ~^9C_3(0.2)^3(0.8)^{9-3}\\\\P(x=3)=0.17616

For x = 4,

P(x=4)= ~^9C_4(0.2)^4(0.8)^{9-4}\\\\P(x=4)=0.06606

So, the required probability would be,

P = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)

P = 0.1342 + 0.3020 + 0.3020 + 0.1762 + 0.0661

P = 0.9805

Therefore, the probability that four or fewer of the people who called will sign up for a class = 0.9805

Learn more about the probability here:

brainly.com/question/3679442

#SPJ4

3 0
11 months ago
How do I do this because it's really confusing haha
frozen [14]
-4/3 is C
-1/3 is B
-1.5 is A
6 0
3 years ago
Genetic drift refers to? :
Damm [24]
The answer is B. Genetic Drift is events that change in a frequency of a gene variant (allele) in a population due to random sampling of organisms.
8 0
3 years ago
The length of a rectangular deck is 5 times its width. If the deck’s perimeter is 24 feet, what is the deck’s area?
spayn [35]

Answer:

20ft²

Step-by-step explanation:

Let the length = L

Let the width = W

Perimeter of a rectangle = 2L + 2W

Translating the word problem into an algebraic equation, we have;

L = 5W .......equation 1

2L + 2W = 24 ........equation 2

To find the width

Substituting equation 1 into equation 2, we have;

2(5W) + 2W = 24

10W + 2W = 24

12W = 24

W = 24/12

Width, W = 2 ft

To find the length;

Substituting the value of "W" into equation 1, we have;

L = 5W

L = 5*2

L = 10 ft

To find the area of the rectangle;

Area = LW

Area = 10*2

<em>Area = 20 ft²</em>

Therefore, the deck's area is 20 feet square.

5 0
3 years ago
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