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Alisiya [41]
3 years ago
7

Need help finding area TuT​

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
The answer to the question is 235.5
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Which of these could be the length of sides of right triangle ABC?
Anna007 [38]

Answer:

C

Step-by-step explanation:

5*5+12*12=13*13

25+144=169

169=169

Hope this helps you!

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This pattern repeats every 4 terms, and the rule is triangle, plus, star, circle. What is the shape in the 16th term of this pat
Alexxandr [17]

Answer:

Fill in the blanks to make the following statements true. Also named the property used.  

a. (-5) + (-4) = ___ + (-5),

b. 4 + __ = 4,

c. - 53 + ___ = - 53,  

d. 4 + [(-5) + (7)] = [4 + (7)] + ___,

e. 25 + [(-50) + 5 ] = (25 + 5) + ___,

f. (-4) + ___ = -4,

g. 4 + (-4) = ___,

h. 5 + ___ = 0 ,

Step-by-step explanation:

Fill in the blanks to make the following statements true. Also named the property used.  

a. (-5) + (-4) = ___ + (-5),

b. 4 + __ = 4,

c. - 53 + ___ = - 53,  

d. 4 + [(-5) + (7)] = [4 + (7)] + ___,

e. 25 + [(-50) + 5 ] = (25 + 5) + ___,

f. (-4) + ___ = -4,

g. 4 + (-4) = ___,

h. 5 + ___ = 0 ,

5 0
3 years ago
IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.
jekas [21]

Using the normal distribution, it is found that 1851 people would have an IQ less than 115.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 100, \sigma = 15

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{115 - 100}{15}

Z = 1

Z = 1 has a p-value of 0.8413.

Out of 2200 people:

0.8413 x 2200 = 1851.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

5 0
1 year ago
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