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castortr0y [4]
3 years ago
15

The equation of a line is y-4=3(x+2) , which of the following is a point on the line?

Mathematics
1 answer:
kramer3 years ago
8 0
Y-4=3(x+2)
y-4=3x+6

y = 3x +10

so in case of choise C. we get 

4 = 3*(-2) +10

4 = -6 +10

4 = 4 

hope this will help you 
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Find an equation of the line that passes through the points (-0.5,0.75) and (0.75,-0.5)
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The equation of the line can be shown using the slope intercept form that is

y= mx+b

where m is the slope and b is the y intercept

So firstly we have to find the value of slope m

To find the value of slope m we apply the formula

m= \frac{( y_{2} - y_{1})}{( x_{2} - x_{1})}

So we can plug the values using the two given points

(-0.5,0.75) and (0.75,-0.5)

m= \frac{(-0.5-0.75) }{(0.75-(-0.5))} = \frac{-1.25}{1.25} = -1

So m = -1

Plug m=-1 in the equation we get

y= -1x +b

Now we have to find the value of b

to find the value of b , we plug any one pint in the equation

0.75 = -1(-0.5) +b

0.75 = 0.5 +b

Subtract 0.5 from both sides

0.25 = b

or

b= 0.25

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y = -1x +0.25

hence the equation of the line is y = -1x +0.25

8 0
3 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46
lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

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3 0
1 year ago
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Answer:

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