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3 years ago

For each problem, identify any important quantities. If it's a known quantity, write the

Mathematics

1 answer:

Tema [17]3 years ago

4 0

Answer:

We have the problem:

"Clare is in charge of getting snacks for a road trip with her friends and her dog. She has

$35 to go to the store to get some supplies. The snacks for herself and her friends cost

$3.25 each, and her dog's snacks costs $9 each."

In this situation we have two variables:

X = number of snacks for herself and her friends that she buys. Each one of these costs $3.50

Y = number of snacks for her dog that she buys. Each one of these costs $9.

The total cost, in this case, can be written as:

X*$3.50 + Y*$9

And we know that she has $35 to spend, so she can spend $35 or less in the store, then we have the inequality:

X*$3.50 + Y*$9 ≤ $35

Where we defined all the quantities in the inequality.

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Will be giving brainliest to the correct one, no links or account will be reported:)

aleksandr82 [10.1K]

Answer:

x = 38

∠P = 26º

Step-by-step explanation:

The sum of the angle in a triangle is 180

x + (x + 78) + (x - 12) = 180

Combine like terms

3x + 66 = 180

Subtract 66 from both sides

3x = 114

Divide both sides by 3

x = 38

-----------------------

∠P = x - 12

∠P = 38 - 12

∠P = 26º

7 0

2 years ago

Read 2 more answers

A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can s

ella [17]

The demand equation illustrates the price of an item and how it relates to the demand of the item.

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

From the question, we have:

$Plates = 300$

$Price = 20$

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

$\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}$

The slope (m) is calculated using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{25-20}{290-300}$

$m = \frac{5}{-10}$

$m = -\frac{1}{2}$

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

$R(x) = (300 - 10x) \times (20 + 5x)$

Open the brackets to calculate the maximum revenue

$R(x) =6000 + 1500x - 200x - 50x^2$

$R(x) =6000 + 1300x - 50x^2$

Equate to 0

$6000 + 1300x - 50x^2 =0$

Differentiate with respect to x

$1300 - 100x =0$

Collect like terms

$100x =1300$

Divide by 100

$x =13$

So, the price at maximum revenue is:

$Price= 20 + 5x$

$Price= 20 + 5 * 13$

$Price= 85$

In conclusion:

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85