For each problem, identify any important quantities. If it's a known quantity, write the

Mathematics

1 answer:

Tema [17]3 years ago

4 0

Answer:

We have the problem:

"Clare is in charge of getting snacks for a road trip with her friends and her dog. She has

$35 to go to the store to get some supplies. The snacks for herself and her friends cost

$3.25 each, and her dog's snacks costs $9 each."

In this situation we have two variables:

X = number of snacks for herself and her friends that she buys. Each one of these costs $3.50

Y = number of snacks for her dog that she buys. Each one of these costs $9.

The total cost, in this case, can be written as:

X*$3.50 + Y*$9

And we know that she has $35 to spend, so she can spend $35 or less in the store, then we have the inequality:

X*$3.50 + Y*$9 ≤ $35

Where we defined all the quantities in the inequality.

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M∠1=28°, m∠6=65°, m∠5=65°. Find m∠MAX

kirill115 [55]

Answer:

<MAX = 93

Step-by-step explanation:

Since <MAX is technically <1 + <5, we know that <1 is 28 and <5 is 65. We can add both of these angles up to solve for <MAX, which is 28 + 65 = 93.

5 0

3 years ago

This trapezium is drawn on a centimetre grid. Find the area of the trapezium.

aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

From the grid :-

$\rm\implies Side_1 = 7 \ units$

$\rm\implies Side_2 = 3 \ units$

$\rm\implies \perp \ Distance =4 \ units$

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

$\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm Area = 20 \ unit^2}$