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stealth61 [152]
3 years ago
11

Will BRAINLY! I need help with this proof.

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0
What are you trying to find? I’m completely lost
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Please help me with this! I will rate you brainliest!!
lesya [120]

do 6x8.(theres two x's and two y's)

3 0
3 years ago
Read 2 more answers
find the length of each isosceles right triangle when the hypotenuse is of the given measure given 8cm
Wewaii [24]

It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is

a^2 +b ^2=c^2

x^2 +x^2 = 8^2

2x^2 = 64

x^2 = 32

x = 4 \sqrt 2

So the length of each leg is 4 \sqrt 2 .

4 0
3 years ago
When n basketball uniforms are purchased, the cost, C, of each uniform is given by the equation.
balandron [24]

Answer:

D. Subtraction property of equality; n = 15

Step-by-step explanation:

Given equation that shows the cost of n basketballs uniforms,

C = 40n + 260

According to the question,

Total cost = $ 860,

⇒ 40n + 260 = 860

Using subtraction property of equality, subtract 260 on both sides,

⇒ 40n = 860 - 260

⇒ 40n = 600

Using division property of equality, divide both sides by 40.

⇒ n = \frac{600}{40} = 15.

Hence, 15 uniforms were purchased.

i.e. Option D is correct.

5 0
3 years ago
Jay buys a new stove for $720. He has 24 months to pay. How much will he pay each month?
LuckyWell [14K]
I think it’s 30 hope that helps
5 0
2 years ago
What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
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