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finlep [7]
2 years ago
10

Atasha jumped 2 1/5 meter in a long jump competition. Arya jumped 1 2/3 meter. Who jumped longer and how many meters?​

Mathematics
1 answer:
Lorico [155]2 years ago
6 0

The person who jumped longer is Atasha by 8/15 meters

<u><em /></u>

<u><em>Who </em></u><u><em>jumped  longer?</em></u><u><em> </em></u>

In order to determine who jumped longer, compare the meters that was jumped by each person. Atasha jumped 2 1/5 meter and Arya jumped 1 2/3 meter. Looking at these fractions, the meters jumped by Atasha is greater than the meters jumped by Arya. This means that Atasha jumped longer.

<u><em>Difference in meters jumped </em></u>

In order to determine the difference, subtract the meters jumped by Arya from the meters jumped by Atasha.

2\frac{1}{5} - 1\frac{2}{3}

1\frac{3 - 10}{15}

\frac{18 - 10}{15}

\frac{8}{15}

To learn more about fractions, please check:

brainly.com/question/11664473?referrer=searchResults

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4 0
3 years ago
Use your calculator to evaluate the limit of x equals 1 to 3 of e raised to the x squared power, dx. Give your answer to the nea
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7 0
3 years ago
Please help ill give brainiest answer
trapecia [35]

Answer:

1: AAS, RQC 2: ASA, SRP

Step-by-step explanation:

(1) We are shown that two angles and one side are congruent in the order of AAS. Make sure you write the letters in terms of the corresponding angles. The angles and sides are congruent because the problem labels it for us. For example, B,A,C=R,Q,S. Answers: AAS, RQC.

(2) We are shown that two angles and one side are congruent in the order of ASA. Make sure you write the letters in terms of the corresponding angles again. For example, P,Q,R=P,S,R. The angles are congruent because the problem labels it for us. Side PR is congruent to side PR by reflexive property. Answers: ASA, SRP.

I hope this helped :) Good luck

4 0
3 years ago
Can you solve : 7x - 4 = 2
Zolol [24]
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8 0
3 years ago
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Two vertical buildings 57 meters apart are 158 meters and 237 meters high. Find the angle of elevation from the top of the short
miskamm [114]

Given :

Two vertical buildings 57 meters apart are 158 meters and 237 meters high.

To Find :

The angle of elevation from the top of the shorter building to the top of the taller building.

Solution :

Distance between height of building, h = 237 - 158 = 79 m.

Distance between these building , d = 57 m.

Now,

tan\ \theta = \dfrac{h}{d}\\\\tan\ \theta = \dfrac{79}{57}\\\\tan\ \theta = 1.386\\\\\theta = tan ^{-1} 1.386\\\\\theta = 54.19^{\circ}

Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.

Hence, this is the required solution.

4 0
3 years ago
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