Answer:
A: 19:26 B:7:8 C:26:45
Step-by-step explanation:
<u>Question A</u>
First to find the ratio between the boys and girls you would add all of the different groups with boys and girls. This would be done by,
<u>Boys</u>
9+10=19
<u>Girls</u>
12+14=26
Now that you have the total number of boys and girls you make this ratio,
19:26
That is the final answer
<u>Question B</u>
For this it is very similar to the boys to girls ratio. You still add the total on each side and then form a ratio. From before you would start by adding both of the different sides which would be done by,
<u>Fifth Graders</u>
12+9=21
<u>Sixth Graders</u>
14+10=24
Now that you have the total number of both of the different grades you make this ratio,
21:24
You can simplify this by finding the lowest common factor which would be
7:8
<u>Question C</u>
To answer this it is very similar to the first two but instead you will find one group and all of the groups to form the ratio. Now you need to add all of the people in each of the groups.
<u>Girls</u>
12+14=26
<u>All</u>
12+9+14+10=45
Now with the total number of both you will form a ratio
26:45
This is your final answer because you cant simplify this any further
The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.
<h3>How to calculate the mean?</h3>
We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.
It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.
In this case, the computation will be:
Class A: Mean = 422/5= 84.4.
Range: 94-74 = 20
Class B: Mean = 418/5 = 83.6.
Range= 88-80 = 8
Learn more about mean on:
brainly.com/question/1136789
#SPJ1
Answer:
Step-by-step explanation:
Answer: 912
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Work Shown:
The starting term is a1 = 3. The common difference is d = 5 (since we add 5 to each term to get the next term). The nth term formula is
an = a1+d(n-1)
an = 3+5(n-1)
an = 3+5n-5
an = 5n-2
Plug n = 19 into the formula to find the 19th term
an = 5n-2
a19 = 5*19-2
a19 = 95-2
a19 = 93
Add the first and nineteenth terms (a1 = 3 and a19 = 93) to get a1+a19 = 3+93 = 96
Multiply this by n/2 = 19/2 = 9.5 to get the final answer
96*9.5 = 912
I used the formula
Sn = (n/2)*(a1 + an)
where you add the first term (a1) to the nth term (an), then multiply by n/2
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As a check, here are the 19 terms listed out and added up. We get 912 like expected.
3+8+13+18 +23+28+33+38 +43+48+53+58 +63+68+73+78 +83+88+93 = 912
There are 19 values being added up in that equation above. I used spaces to help group the values (groups of four; except the last group which is 3 values) so it's a bit more readable.
Answer:
25
Step-by-step explanation:
you just multiple 5 times 5
