Answer:
The graph in the attached figure
Step-by-step explanation:
we have

This is a exponential function of the form

where
a is the initial value or the y-intercept
b is the base of the exponential function
If b>1 then is a exponential growth function
If b<1 then is a exponential decay function
In this problem
The y-intercept is equal to
For x=0

The y-intercept is the point (0,1)
so


The value of b is greater than 1
so
Is a growth function
To plot the graph create a table with different values of x and y
For x=-1
f(x)=2^-1=0.5
point (-1,0.5)
For x=1

point (1,2)
For x=2

point (2,4)
For x=3

point (3,8)
For x=4
f(x)=2^4=16
point (4,16)
Plot the y-intercept and the other points and connect them to graph the exponential function
Note that as x increases the value of y increases (exponential growth function)
The graph in the attached figure