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riadik2000 [5.3K]
3 years ago
15

Find the number of permutations of the first 8 letters of the alphabet taking 4 letters at a time.

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0
1680 hope it helps :)

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Linear equation 1/2X+Y=6
krek1111 [17]
You can graph it but cant answer it because there is two variables so try and change it to slope intercept form do you know how ???????

5 0
3 years ago
Whoever gets this right gets brainlyess answer and it's worth 10 points :)
babymother [125]
A=$20.20/10gal=$2.02 per gal

B=$26.04/12gal=$2.17 per gal

C=$28.14/14gal=$2.01 per gal

D=$30.45/15gal=$2.03 per gal

So C is the cheapest per gallon.
3 0
3 years ago
Please help extremely confused
svetlana [45]

Answer:

basic geometry and trig ratios

Step-by-step explanation:

sin 10 = 500/x

x = 500/sin 10

x = 2 879,4 m

8 0
2 years ago
A cup of milk has 10 grams of protein. How much protein is in 2.5 cups of milk?
Sedaia [141]

Answer:

25 grams of protein

Step-by-step explanation:

10 grams of protein is in 1 cup of milk.

To understand how many grams of protein are in 0.5 cups of milk, I would need to divide 10 by 2, to get 5.

There are 5 grams of protein in 0.5 cups of milk.

Now if I want to see how many grams of protein are in 2 cups of milk, I would multiply 10 by 2, to get 20.

There are 20 grams of protein in 2 cups of milk.

But, the question is asking for how much protein is in 2.5 cups of milk.

Since we know how much is in 2 cups, and 0.5, we can just add them together, because 2+0.5 is 2.5.

20+5 is 25 grams.

There are 25 grams of protein in 2.5 cups of milk.

6 0
3 years ago
11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

3 0
3 years ago
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