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3 years ago

On the exam, Rebecca successfully created 20 out of 25 vases.

Mathematics

2 answers:

juin [17]3 years ago

7 0

$\text{Hello there! :]}$

$\large\boxed{125 \text { vases}}$

$\text{To solve, find the proportion of successes from the total:}\\\\20 / 25 = 4 / 5\\\\\text{Set up a proportion to find the # of vases necessary to complete 100 successfully:}\\\\\frac{20}{25} = \frac{100}{x} \\\\\text{Cross multiply to solve:}\\\\20 * x = 100 * 25\\\\20x = 2500\\\\\text{Divide both sides by 20:}\\\\x = 125 \text{ vases}$

zaharov [31]3 years ago

3 0

Answer:

125=_=_=

Step-by-step explanation:

hoped I helped

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

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Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

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$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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