It is 3 to 4
you find the GCF of 24 and 32 which is 8. then divide 24 and 32 by 8 to find the ratio
Answer:
the second one
Step-by-step explanation:
We can use the fact that, for
,

Notice that
![\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Cdfrac1%7B1-x%7D%5Cright%5D%3D%5Cdfrac1%7B%281-x%29%5E2%7D)
so that
![f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdisplaystyle%5Cfrac5%7B%281-x%29%5E2%7D%3D5%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Csum_%7Bn%3D0%7D%5E%5Cinfty%20x%5En%5Cright%5D)



By the ratio test, this series converges if

so the series has radius of convergence
.
Answer:
mean = 4
medin = violet
mode = light blue
range = 4
Step-by-step explanation:
mean = sum/no
mode = largest number
median = (n+1)/2th item
rnge = largest - smllest
Answer:
(-1, -9)
Step-by-step explanation:
Recall that for 2 points (x1, y1) and (x2,y2)
the midpoints are given by
x ordinate =
y ordinate = 
In our case x1 = 8, y1 = -10, x2 = -10, y2=-8
x ordinate =
= [8 + (-10) ] / 2 = -1
y ordinate =
= [-10 + (-8) ] / 2 = -9
hence midpoint is (-1, -9)