Given:
area of square, A = 16
error in area, dA = 0.03 cm^{2}
Step-by-Step Explanation:
Let 'a' be the side of the square
area of square, A = (1)
A = 16 =
Therefore, a = 4 cm
for max tolerable error in length 'da', differentiate eqn (1) w.r.t 'a':
dA = 2a da
da =
da = 0.0375 cm
<u>ANSWER: </u>
70 students like both nepali and maths.
<u>SOLUTION: </u>
Given,out of 200 students in a class. 150 like math, 120 like nepali.
The number of students who like nepali only is one third of the students who like math .
We need to find how many likes both subjects.
Let, the number of students who like only nepali be x.
Then, x is one-third of students who like maths.
x = students who like maths
Now, out of 120 students who like nepali, only 50 students like nepali alone, which means remaining students like both nepali and maths
Students who like both subjects = 120 – 50 = 70.
Hence,70 students like both nepali and maths.