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3 years ago

What is the equation of a line that passes through the points (–3, 4) and (2, 8)?

Mathematics

2 answers:

N76 [4]3 years ago

4 0

Answer:

Step-by-step explanation:

(–3, 4) and (2, 8)

y2 = 8, y1 = 4, x2 = 2 and x1 = -3

Slope m = {y2-y1}/{x2-x1}

m = {8 - 4}/{2 - (-3)}

m = 4/(2+3)

m = 4/5

And

y - y1 = m(x - x1)

y - 4 = 4/5(x - (-3))

y - 4 = 4/5(x + 3)

Multiply each term by 5

5y - 20 = 4(x + 3)

5y - 20 = 4x + 12

5y = 4x + 20 + 12

5y = 4x + 32

Dividing by 5

y = 4x/5 + 32/5

y = 0.8x + 6.4

GREYUIT [131]3 years ago

3 0

Answer:

Step-by-step explanation:

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$\bf n^{th}\textit{ term of a geometric sequence}\\\\
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