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beks73 [17]
3 years ago
10

5. Write a real-world problem that can be represented by the expression 21 + (12 x 2).

Mathematics
1 answer:
Setler [38]3 years ago
5 0

Step-by-step explanation:

Anna Bought 3 Toys each worth 7$. after the purchase, it is announced that the price of the toys has risen to 12$, and Anna decides to Buy 2 More toys before the price rises again. in total, how much did Anna Spend?

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solmaris [256]
The first question is clearly incomplete. The model is not presented so we cannot estimate the volume of the flask but if it was given, the volume is equal to the volume of the cylinder plus the sphere. The cylinder volume is V = pi(r^2)h. 

To find the volume of the sphere we use the given equation <span>4/3πr^3. The radius is 4.5/2. The volume is 47.71 cubic inches. </span>
6 0
3 years ago
During the summer, Alex earns some money mowing his neighbors' lawns. He is being paid $6.00 per hour. In June, he worked 11 hou
ludmilkaskok [199]
19 x 6= $114
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5 0
3 years ago
Read 2 more answers
Graph the solution of this inequality:<br>4/9x-10&gt;x/2-12​
Darya [45]

Answer:

see below

Step-by-step explanation:

4/9x-10>x/2-12​

Subtract 4/9 from each side

4/9x-4/9x-10>x/2 - 4/9x-12​

-10>x/2 - 4/9x-12

Add 12 to each side

12-10>x/2 - 4/9x

2 > x/2 - 4/9x

Get a common denominator

2 > 9x/18 - 8x/18

2 > x/18

Multiply each side by 18

2*18 > x

36 >x

Open circle at x

Line going to the left

4 0
3 years ago
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

⇒ S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})

All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

4 0
3 years ago
3*3*3*3= 81 is an example of ___
mash [69]

Answer:

expanded I believe or the first one good luck

7 0
3 years ago
Read 2 more answers
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