Answer:
-1.92 cm³
Step-by-step explanation:
The formula for the volume of a cube in terms of side length is ...
V = s³
Then the first-order approximation of volume for a small change ∆s in side length is ...
V(s +∆s) ≈ V(s) + V'(s)·∆s
and the change in volume is ...
∆V ≈ V(s +∆s) -V(s) = V'(s)·∆s
The derivative V'(s) is ...
V'(s) = 3s²
so the change in volume for s = 8 cm and ∆s = -0.01 cm is ...
∆V ≈ 3s²·∆s = 3(8 cm)²(-0.01 cm) = -1.92 cm³
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Answer:
The right answer is "5.9". A further solving is provided below.
Step-by-step explanation:
The given values are:
Initial Magnitude,
M₁ = 3.9
Let Second magnitude be M₂.
Now,
⇒ 
On substituting the values, we get
⇒ 
On putting the value of "log 120", we get
⇒ 
On adding "3.9" both sides, we get
⇒ 
⇒ 
Answer:
$21.58
Step-by-step explanation:
580 ÷ 100 = 5.8
$10.36 × 5.8 = $60.088
$6.64 × 5.8 = 33.512
I did this and that’s the correct answer. I hope it helps…
Answer:
b
Step-by-step explanation: