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2 years ago

Find the circumference and the area of a circle with radius 9 .

Mathematics

1 answer:

Eduardwww [97]2 years ago

6 0

C=2(pi)r use this equation with 9 in place of r

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9. Your bank account has a balance of $145.67. You make a withdrawal

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There is $103.15 in your bank account.

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3 years ago

Which value of n makes the equation true?

Anettt [7]

Where’s the equation?

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2 years ago

What is the product of the polynomial (7x+7) (x+2)

kolbaska11 [484]

Answer: 7x^2+21x+14

Step-by-step explanation:

(7x+7)(x+2)

Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

7x×x+7x×2+7x+7×2

↘ ↙

7x×x calculate product

7x^2+7x×2+7x+7×2

↘ ↙

7x×2 calculate product

7x^2+14x+7x+7×2

↘↙

7×2 multiply numbers

7x^2+14x+7x+14

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21x collect like terms

7x^2+21x+14 is your end result.

3 0

2 years ago

Given the rule: an=7(1/2)n-1 identify the first term

Shkiper50 [21]

Answer:

using the rule given: 2.5
using an exponential rule: 7

Step-by-step explanation:

Evaluating the linear rule given, for n = 1, we have ...

a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5

_____

We suspect you may intend the exponential function ...

an = 7(1/2)^(n-1)

Then, for n = 1, we have ...

a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7

_____

When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.

3 0

3 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago