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Katen [24]
3 years ago
15

Can you please help me ?

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
First ones are A and A
VLD [36.1K]3 years ago
6 0

Answer:

1. 6

2. <

3. <

Step-by-step explanation:

1. if you owe someone 6 dollars and you have 12 you are left with 6

2 and 3. the number closest to 0 is bigger than the one farthest

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Take a look at the picture and answer correctly so i can mark you as brainliest.
AVprozaik [17]

Answer:

{-5, -4, -2, -1, 2, 3}

Step-by-step explanation:

Domain is x value and then you have to put in order :)

5 0
3 years ago
Read 2 more answers
$28,000 invested at a rate of 4% compounded annually; 5 years
sasho [114]
$28<span> compounded on a </span>Yearly<span> basis over the course of </span>5<span> years at a </span>4% interest rate would be worth:

<span>$34</span>
4 0
3 years ago
Read 2 more answers
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
3 years ago
Given the following function, find f(-2), f(0), and f(1).<br> f(x) = x2 + 3<br> =
WARRIOR [948]

Answer:

jjjjnnuiuhjiihhiihb

Step-by-step explanation:

tyuijiojnoo.

yu8ijhiihj

7 0
2 years ago
Read 2 more answers
The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
2 years ago
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