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Katen [24]
3 years ago
15

Can you please help me ?

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
First ones are A and A
VLD [36.1K]3 years ago
6 0

Answer:

1. 6

2. <

3. <

Step-by-step explanation:

1. if you owe someone 6 dollars and you have 12 you are left with 6

2 and 3. the number closest to 0 is bigger than the one farthest

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HELP ASAP!right answer I’ll give you a crown
faltersainse [42]

Answer:

y=-\frac{3}{2}x+1

Step-by-step explanation:

Slope-intercept form means

y=mx+c

where m is given its the slope which is -\frac{3}{2} and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,

y=mx+c

-5 = -\frac{3}{2}(4)+c

-5=-6+c

c=1

now we know the value of slope which is given -\frac{3}{2} and we found the value of which is 1 so we put these values into our original slope-intercept form equation

y=mx+c\\\\y=-\frac{3}{2}x+1

4 0
2 years ago
4/r ​ = 5/7 need help please
Annette [7]
The answer to the question is

5r= 28

r= 28/5
7 0
3 years ago
Mrs. Toomer brought 40 cookies to school. Mrs. Toomer's class ate 1/2 the cookies. Mrs. Wilson's class ate 1/4 of the remaining
Arte-miy333 [17]
1/2 of 40 is 20, and the question says 1/4 of the REMAINING cookies, and 1/4 of 20 is 5. There are 3/4 left, or 15 cookies. I hope this helps!
3 0
3 years ago
Read 2 more answers
Express the equation in rectangular form<br> a) r = 2sin(2Θ)<br> b) r = 4cos(3Θ)
Dafna11 [192]

Answer:

a.  sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b.  (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know  sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r  and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2)  and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that  sin theta = y/r  and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know  r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

5 0
3 years ago
Is (4 + 4x0)2x a monomial? What about (4 + 4x2)2x?
viktelen [127]
4xtB equals to 75x+90 equals to X squares
3 0
3 years ago
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