Let X be the width of the path.
The width of the path would be the width of the pool plus 2x, so 2x +16
The length of the path would be the length of the pool plus 2x, so 2x+22
The total area is 832 square feet.
Area is found by multiplying the length by the width.
So you have:
(2x+16) (2x+22) = 832
Use the Foil Method:
(2x+16) (2x+22) = 4x^2 +76x+352
Now you have:
4x^2 +76x+352 = 832
Subtract 832 from both sides:
4x^2 +76x+352-832 = 0
Simplify:
4x^2 +76x -480
Factor the left side:
4(x-5)(x+24) = 0
Divide both sides by 4:
(x-5)(x+24) = 0
Set both parenthesis to equal 0 and solve for x:
x=5 and x = -24
The width of the path cannot be a negative number, so the width is 5 meters.
Answer:
i need a picture of the sketch
Hello!
Let's subtract the eight DVDs Joe received as gifts, because he didn't buy them on his own.
35 - 8 = 27
Now, divide the remaining CDs by the 3 years he collected his DVDs in.
27 ÷ 3 = 9
A N S W E R:
Joe bought 9 DVDs last year.
Good day!
Use same-length line segments to solve for x and y.
... PS = SR
... 4x +4 = 7x -17
... 21 = 3x . . . . . . . . . add 17-4x
... 7 = x . . . . . . . . . . . divide by 3
... PS = SR = 4·7+4 = 32
... PQ = QR
... 5y -31 = 2y +5
... 3y = 36 . . . . . . . . . add 31-2y
... y = 12 . . . . . . . . . . . divide by 3
... PQ = QR = 2·12 +5 = 29
... PT = TR = 6·7-2·12 = 18
