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Answer:
Part A: 2 ft²
Part B: draw a diagonal (AC, for example); 1 ft²
Step-by-step explanation:
<u>Part A</u>:
The area of a parallelogram is given by the formula ...
A = bh
where 'b' is the length of the base, and 'h' is the perpendicular distance between the bases.
Using the numbers shown on the diagram, the area is ...
A = (3 ft)(2/3 ft) = 3·2/3 ft²
A = 2 ft² . . . . . area of the parallelogram
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<u>Part B</u>:
Typically, a polygon is partitioned into triangles by drawing diagonals from one of the vertices. It does not matter which one. (In a quadrilateral, only one diagonal can be drawn from any given vertex.) Here, the "base" of each triangle is the same as the base of the parallelogram: 3 feet. The "height" of each triangle is the same as the height of the parallelogram: 2/3 ft.
The area of a triangle is given by the formula ...
A = 1/2bh
A = 1/2(3 ft)(2/3 ft) = (1/2)(3)(2/3) ft²
A = 1 ft² . . . . . . . . area of each triangle
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<em>Additional comment</em>
It should be no surprise that the area of each of the two congruent triangles is 1/2 the area of the parallelogram.
