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Serggg [28]
3 years ago
6

Find the missing side length, and enter your answer in the box below. If

Mathematics
1 answer:
fredd [130]3 years ago
8 0

Answer:

i need a picture of the sketch

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lara31 [8.8K]
I think you just subtract 59 and 11 but i could be wrong
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Triangle ABC is reflected across the y-axis to form the image A'B'C'. Triangle A'B'C' is then reflected across the x-axis to for
Anestetic [448]

Answer:

Circular!

Step-by-step explanation:

Triangle ABC is reflected across the y-axis to form the image A'B'C'. Triangle A'B'C' is then reflected across the x-axis to form the image A''B''C''. What type of rotation can be used to describe the relationship between triangle A"B"C" and triangle ABC

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Which statement is true about the points (-4,6) and (4,-6) is true
White raven [17]

Answer:

D.

Step-by-step explanation:

I graphed it. They are both not in the same qudrant because both their x and y values are opposites. This led me to believe that they were in quadrants digaonal of each other, meaning the answer was D, because if you flipped the point across the x or y axis and then flipped it again across the other axis, it would be that point. Just in case, I graphed it. Please tell me if I'm wrong :)

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3 years ago
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What gives the range of the function y=|x-1|+7
riadik2000 [5.3K]
The rage of the function is x=-6
6 0
4 years ago
Given that (7x-8)/(2x-1)(x-2) <br><br> Use Partial Fraction Decomposition to Find A and B.
koban [17]

We look for constants <em>a</em> and <em>b</em> such that

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac a{2x-1} + \frac b{x-2}

Rewrite all terms with a common denominator and set the numerators equal:

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)}{(2x-1)(x-2)} + \frac{b(2x-1)}{(x-2)(2x-1)} \\\\ \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)+b(2x-1)}{(2x-1)(x-2)} \\\\ \implies 7x-8 = a(x-2) + b(2x-1) = (a+2b)x - 2a - b

Then

<em>a</em> + 2<em>b</em> = 7

-2<em>a</em> - <em>b</em> = -8

Solve for <em>a</em> and <em>b</em>. Using elimination: multiply the first equation by 2 and add it to the second equation:

2 (<em>a</em> + 2<em>b</em>) + (-2<em>a</em> - <em>b</em>) = 2(7) + (-8)

2<em>a</em> + 4<em>b</em> - 2<em>a</em> - <em>b</em> = 14 - 8

3<em>b</em> = 6

<em>b</em> = 2

Then

<em>a</em> + 2(2) = 7   ==>   <em>a</em> = 3

and so

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac 3{2x-1} + \frac 2{x-2}

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3 years ago
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