Answer:
True
Step-by-step explanation:
This is true. x + 25 equals 40 in both cases, so they're equal.
Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:
In which a is the probability that a customer saw the advertisement on the internet but not on television and 
is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:
12% saw it on both the internet and on television.
This means that 
20% saw it on television
This means that 
37% of customers saw the advertisement on the internet
This means that 
What is the probability that a randomly selected customer saw the advertisement on the internet or on television
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Answer:
83.3%
Step-by-step explanation:
The probability of rolling a 3 on a 6-sided dice is 1/6
Since you don't want a three, there's a 5/6 chance of not rolling a 3
5/6 (use calculator and divede 5 by 6) = 0.833333 (move decimal 2 to the right) = 83.3%
Therefore, the most reasonable answer would be C, 83.3%
Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer:
hello!
Step-by-step explanation:
I say u can go for option B
hope it helps!
