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PilotLPTM [1.2K]
2 years ago
7

(For this equation any non-integer values should be entered as fractions)

Mathematics
1 answer:
bazaltina [42]2 years ago
8 0
<span> y = 2/7 x - 1/7
slope = 2/7
</span><span>perpendicular  lines, slope is opposite and reciprocal
</span>so slope of new line = -7/2
<span>passes through the point (9,-32)
</span><span>slope-intercept form: y = mx + b
so
b = y - mx
b = -32 - (-7/2)(9)
b = -32 + 63/2
b = -1/2

equation in </span>slope-intercept form:
y = -7/2 x - 1/2
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Who’s the the y-value of the vertex of the function f(x)=-(x+8)(x-14)
Ksju [112]

Answer:

The required y-value is -121.

Step-by-step explanation:

There are several ways in which we could approach this problem.  From the two binomial factors (x + 8) and (x - 14), we know that the two roots are x = -8 and x = 14.  The axis of symmetry is the vertical line x = 3.  This value is halfway between x = -8 and x = 14.

Substituting x = 3 into  f(x)= -(x+8)(x-14) results in f(3) = -(11)(-11) = -121.

The vertex is at (3, -121).  The required y-value is -121.

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Answer:

→(6.2 \times  {10}^{ - 2} ) \times (2 \times  {10}^{6} ) \\ =  (6.2 \times 2) \times ( {10}^{ - 2}  \times  {10}^{6} ) \\ =  12.4 \times  {10}^{( - 2 + 6)}  \\  =12.4 \times  {10}^{4}  =  \boxed{124000}✓

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mars1129 [50]
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First of all, are you able to graph these two lines?  Secondly, can you read the coordinates of the point of intersection from the graph?

I urge you to try graphing these lines and determining the point of intersection.

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3 0
3 years ago
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