Answer:
We accept H₀ . We don´t have enough evidence to express the publisher claim is not true
Step by Step explanation:
We must evaluate if the mean of the price of college textbooks is different from the value claimed by the publisher
n < 30 then we must use t - distrbution
degree of freedom n - 1 df = 22 - 1 df = 21
As the question mentions " different " that means, a two-tail test
At 0,01 significance level α = 0,01 α/2 = 0,005
and t(c) = 2,831
Test Hypothesis
Null Hypothesis H₀ μ = μ₀
Alternative hypothesis Hₐ μ ≠ μ₀
To calculate t(s)
t(s) = ( μ - μ₀ ) /σ/√n
t(s) = ( 433,50 - 385 ) / 86,92 / √22
t(s) = 2,6171
Comparing t(c) and t(s)
t(s) < t(c)
Then t(s) is in the acceptance region we accept H₀. We don´t have enough evidence to claim that mean price differs from publisher claim
Answer:
There are no values that are outliers.
Well, 50*6-x=265, so 300-x=265, so x=300-265=35
Done this in elementary /:)
Answer: (5,25)
Step-by-step explanation: Use the formula x = -b/2a to find the maximum and minimum
The rate at which Riya is applying the mulch to the garden is 250000:1.
<h3>What is the rate?</h3>
It should be noted that rate is simply used to show the relationship between two things. A rate in mathematics is the comparison of two related values expressed in different units. The numerator of the ratio expresses the corresponding rate of change in the dependent variable if the denominator of the ratio is written as a single unit of one of these quantities and it is assumed that this quantity may be modified systematically (i.e., is an independent variable).
Per unit of time is a frequent sort of rate, and examples include speed, heart rate, and flux. Exchange rates, literacy rates, and electric field ratios are examples of ratios with a non-time denominator (in volts per meter).
From the information, Riya is applying mulch to the garden and she applied at a rate of 250000cm³ for every m² of space.
Therefore, the rate at which Riya is applying the mulch to the garden is 250000:1.
Learn more about rate on:
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