2f(x) = 2x - 4 [0, 3]3f(x) = 3x - 1 [-2, -1]9f(x) = x² [4, 5]4f(x) = 4x [5, 20]5f(x) = x² - 3 [0, 5]1f(x) = x + 10 [-5, -1]10f(x) = 10x [-3, 0]¹/₂f(x) = 0.5x - 2 [2, 4]11f(x) = 2x² + x [1, 4]-1f(x) = -x + 2 [-3, 5]Domainthe set of all reasonable input values of x for the functionRangeset of output y values for the domain of the functionAverage Rate of ChangeChange in values over a given interval.Origin(0,0) on the coordinate graphing system; where the two axes meetx-axisthe horizontal number line in the coordinate systemy-axisthe vertical number line in the coordinate systemCoordinatesany specific (x,y) in the coordinate systemx-interceptwhere the function intersects the x-axisy-interceptwhere the function intersects the y-axis; the b value in a linear functionLinear FunctionA function whose graph is a straight line, where the average rate of change (slope) is constant.Exponential FunctionA function where the average rate of change is not constant and whose input value is an exponent.Table of ValuesA table showing two sets of related numbers<span>Slope of line through the points (-2, 3) and (0,0) m = (0 - 3) / (0 - -2) = -3/2</span><span>Average Rate of Change on the interval [-2, 0]</span>Slope: m = "rise over run" = 2Rate of Change<span>Slope of line through the points (5, -1) and (0,0) m = (0 - -1) / (0 - 5) = -1/5</span><span>Average Rate of Change on the interval [0, 5]</span><span>Slope of line through the points (0, 16) and (4, 21) m = (21 - 16) / (4 - 0) = 5/4</span>Average Rate of Change over the interval [0,4]
First find the slope using the two points (2,225) and (5,480) (480-225)/(5-2) = 85 Then find b. 225 = 85*2 + b 225 = 170 + b 55 = b y = 85x + 55 OR f(x) = 85x + 55 This is the answer to PART B. Standard form PART A is 85x - y = 55 PART C Plot the y intercept, 55. From the y intercept count the slope 85 up right 1 and plot a point, draw a line through the points The x axis is the number of days so it would be in intervals of 1. The y axis is money, I would do intervals of $5
When two triangles are congruent they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there.
The answer is yes they are congruent because if you flip the second one they are the same.
