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MA_775_DIABLO [31]
2 years ago
8

Which graph shows a set of ordered pairs that represents a function?

Mathematics
1 answer:
IrinaVladis [17]2 years ago
6 0

Answer:

2nd Graph

General Formulas and Concepts:

<u>Algebra I</u>

  • Vertical Line Test - A function's x-values must have only 1 corresponding y-value. If the function fails this test, it is not a function.

Step-by-step explanation:

When we apply the Vertical Line Test to the 1st graph, it does not pass (x = 1). Therefore, the 1st graph is not a function.

When we apply the Vertical Line Test to the 2nd graph, it does pass. Therefore, the 2nd graph is a function.

When we apply the Vertical Line Test to the 3rd graph, it does not pass (x = 2). Therefore, the 1st graph is not a function.

When we apply the Vertical Line Test to the 4th graph, it does not pass (x = -3). Therefore, the 4th graph is not a function.

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Suppose theta is an angle in the standard position whose terminal side is in quadrant 4 and cot theta = -6/7. find the exact val
zimovet [89]

First off, let's notice that the angle is in the IV Quadrant, where sine is negative and the cosine is positive, likewise the opposite and adjacent angles respectively.

Also let's bear in mind that the hypotenuse is never negative, since it's simply just a radius unit.

\bf cot(\theta )=\cfrac{\stackrel{adjacent}{6}}{\stackrel{opposite}{-7}}\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{6^2+(-7)^2}\implies c=\sqrt{36+49}\implies c=\sqrt{85} \\\\[-0.35em] ~\dotfill

\bf tan(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{adjacent}{6}} ~\hfill csc(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{opposite}{-7}} ~\hfill sec(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{adjacent}{6}} \\\\\\ sin(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{sin(\theta)=\cfrac{-7}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies sin(\theta)=-\cfrac{7\sqrt{85}}{85}}

\bf cos(\theta)=\cfrac{\stackrel{adjacent}{6}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{cos(\theta)=\cfrac{6}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies cos(\theta)=\cfrac{6\sqrt{85}}{85}}

6 0
2 years ago
SOMEONE PLEASE HELP! I'LL THANK YOU AND RATE 5 STARS AND MARK BRAINLIEST IF I CAN!!
viktelen [127]
Slope of AB=(2-3)/(1+1)=-1/2; AC=(-1-3)/(-3+1)=-4/-2=2; BC=(-1-2)/(-3-1)=-3/-4=3/4.
The product of two sides that are perpendicular is -1. Slopes of AB and AC are perpendicular so angle A is a right angle. ABC is a right-angled triangle.
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3 years ago
1+231 divided by 223,123
guapka [62]

Answer:

1.0010353034

Step-by-step explanation:

6 0
2 years ago
( x + 2 )^2 - ( y + 2 )^2
GarryVolchara [31]

The difference of two squares factoring pattern states that a difference of two squares can be factored as follows:

a^2-b^2 = (a+b)(a-b)

So, whenever you recognize the two terms of a subtraction to be two squares, you can factor it as the sum of the roots multiplied by the difference of the roots.

In this case, the squares are obvious: (x+2)^2 is the square of x+2, and (y+2)^2 is the square of y+2

So, we can factor the expression as

(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)] - [(x+2)+(y+2)]

(the round parenthesis aren't necessary, I used them only to make clear the two terms)

We can simplify the expression summing like terms:

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3 0
3 years ago
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tiny-mole [99]

Answer:

The value of x is -9, 3/4 and 3.

Step-by-step explanation:

In order to find the value of x, tou have to let f(x) equals to 0 :

Let f(x) = 0,

(x-3)(x+9)(4x-3) = 0

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x = 3

x + 9 = 0

x = -9

4x - 3 = 0

4x = 3

x = 3/4

7 0
3 years ago
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