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Natasha2012 [34]
2 years ago
8

Simplify. Your answer should contain only positive exponents.

Mathematics
1 answer:
saveliy_v [14]2 years ago
6 0

Answer:

Step-by-step explanation:

7.

2y² * 3x = 6xy²

8.

4v³ * vu²

= 4 \times 1 \times (v^{3+1})( u^2)

= 4v⁴u²

9.

4a³b² * 3a⁻⁴b⁻³

= 4 \times 3 \times a^{(3+(-4))} \times b ^{(2+(-3))}

= 12a⁻¹b⁻¹

= \dfrac{1}{12ab}

10.

x²y⁻⁴ * x³y²

= x^{2+3}y^{(-4)+2}

= x^{5}y^{-2}

= x^{5} \times \dfrac{1}{y^{2}}

11.

(x²)⁰ = 1

12.

(2x²)⁻⁴

= (2^{-4} \times x^2^{(-4)})

= \dfrac{1}{16x^8}

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Across which axis was point A reflected​
Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

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4 0
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Step-by-step explanation:

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