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VashaNatasha [74]
3 years ago
15

Use the coordinates of the labeled point to find a point slope equation of the line

Mathematics
2 answers:
Georgia [21]3 years ago
5 0

The answer to this question is C. y + 2 = -2 (x - 4)

Aloiza [94]3 years ago
3 0

Answer:

C) y+2 = -2(x-4)

Step-by-step explanation:

Point-slope form of an equation is

y - y₁ = m(x - x₁)

The point we have is (4, -2); this gives us

y - -2 = m(x - 4)

y + 2 = m(x - 4)

The line decreases; this means the slope must be -2 instead of 2.  This gives us

y + 2 = -2(x - 4)

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Given the rectangle below, find the measure of
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4 years ago
Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
2 years ago
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