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SVETLANKA909090 [29]
3 years ago
15

I NEED HELP ASAP PLEASE

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

Step-by-step explanation:

Yo when you get these kind of questions you can use desmos calculator, for the future.

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B

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Rewrite the equation by completing the square. x^{2}+16x+64 = 0
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(x+8)²

Step-by-step explanation:

x² + 16x + 64 = (x+8)²

(x+8)² = (x+8)(x+8) = x*x + x*8 + 8*x + 8*8 = x² + 8x + 8x + 64

         = x² + 16x + 64

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Read 2 more answers
Let f(x) be a polynomial such that f(cos θ) = cos(4) θ for all θ. Find f(x). (This is essentially the same as finding cos(4) θ i
Galina-37 [17]

Answer:

f(x) = 8x⁴-8x²+1

Step-by-step explanation:

I will assume that f(cos θ) = cos(4θ). Otherwise, f would not be a polynomial. lets divide cos(4θ) in an expression depending on cos(θ). We use this properties

  • cos(2a) = cos²(a) - sin²(b)
  • sin(2a) = 2sin(a)cos(a)
  • sin²(a) = 1-cos²(a)

cos(4θ) = cos(2 * (2θ) ) = cos²(2θ) - sin²(2θ) = [ cos²(θ)-sin²(θ) ]² - [2cos(θ)sin(θ)]² = [cos²(θ) - ( 1 - cos²(θ) ) ]² - 4cos²(θ)sin²(θ) = [2cos²(θ)-1]² - 4cos²(θ) (1 - cos²(θ) ) = 4 cos⁴(θ) - 4 cos²(θ) + 1 - 4 cos²(θ) + 4 cos⁴(θ) = 8cos⁴(θ) - 8 cos²(θ) + 1

Thus f(cos(θ)) = 8 cos⁴(θ) - 8 cos²(θ) + 1, and, as a result

f(x) = 8x⁴-8x²+1.

5 0
3 years ago
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