A ball is thrown from a point 6 meters above the ground

Solve for x, rounding to the nearest hundredth.

Andreas93 [3]

Answer: x=1.32
Hope this helps!

6 0

2 years ago

20 square root of 270 /4 square root of 3

OleMash [197]

Answer:

<u>The most simplified form is 15√10</u>

Step-by-step explanation:

1. Let's simplify the expression:

20√270 ÷ 4√3

20√9 * 30/ 4√3 (√270 = √9 * 30)

60 √30/ 4√3

(60 √3 * √10) / 4√3 (√30 = √3 * √10)

60/4 √10 ( We cancel √3 in the numerator and in the denominator)

15√10

<u>The most simplified form is 15√10</u>

6 0

3 years ago

Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min

mylen [45]

Answer:

The rate of change is $108\pi$ ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

$A(t) = \pi r^{2}$

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

$\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}$

We have that:

$\frac{dr}{dt} = 6, r = 9$ .

We want to find $\frac{dA}{dt}$

So

$\frac{dA(t)}{dt} = 2\pi*9*6$

$\frac{dA}{dt} = 108\pi$

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is $108\pi$ ft^(2)/min

5 0

3 years ago

Write an algebraic expression to represent each statement<br> 50 added to half of a number, c

Fittoniya [83]

The expression represented by 50 added to half of a number, c is 50 + c/2

<h3>What are expressions?</h3>

Expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to translate the algebraic expression?</h3>

The expression is given as

50 added to half of a number, c

half of a number, c means divide c by 2

So, we have

50 added to half of a number, c => 50 added to c/2

Added to means +

So, we have

50 added to half of a number, c => 50 + c/2

Hence, the expression represented by the statement is 50 + c/2

Read more about expressions at

brainly.com/question/22019327

#SPJ1

7 0

1 year ago

Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago