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IgorC [24]
4 years ago
12

Pls I need answer on number 7. I’m not sure if it’s 11 or 12.

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0
The answer is letter A
Alik [6]3 years ago
4 0
My argument is...
if the number of weeks is greater than 11
and 11 is not greater than 11
but 12 is greater than 11
then b
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What is the distance between point A and B , to the nearest tenth ?
kondaur [170]
I can’t see where they are
6 0
3 years ago
What is the answer to 1n-10=5/6-7-1/3n
navik [9.2K]
1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7

1*n-((5/6)*n)+(1/3)*n-10+7 = 0

n+(-5/6)*n+(1/3)*n-10+7 = 0

1/2*n-3 = 0 // + 3

1/2*n = 3 // : 1/2

n = 3/1/2

n = 6

That's just in case you had to show your work lol^^
3 0
3 years ago
Read 2 more answers
Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
OlgaM077 [116]

Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

3 0
3 years ago
Surds and roots<br> look at picture
FinnZ [79.3K]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Expand & simplify ⇨ ( \sqrt{10}  -  \sqrt{2} ) ^{2}. Give your answer in the form b - c \:  \sqrt{5} where b & c are integers.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

( \sqrt { 10 } - \sqrt { 2 } ) ^ { 2 }

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{10}-\sqrt{2}\right)^{2}.

\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}

The square of \sqrt{10} is 10.

10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}

Factor 10=2\times 5. Rewrite the square root of the product \sqrt{2\times 5} as the product of square roots \sqrt{2}\sqrt{5}.

10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}

Multiply \sqrt{2} and \sqrt{2} to get 2.

10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}

Multiply -2 and 2 to get -4.

10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}

The square of \sqrt{2} is 2.

10-4\sqrt{5}+2

Add 10 and 2 to get 12.

\boxed{ \boxed{\bf\:12-4\sqrt{5} }}

  • Here, b & c are integers where \boxed{ \sf \: b = 12 \: and \: c = 4}
7 0
3 years ago
Read 2 more answers
Cassidy dropped a ball from a height of 46 yards. After each bounce, the peak height of the ball is half the peak height of the
iragen [17]
1) Initial fall => 46 yards


2) First bounce = > rising 46/2 yards and falling the same => 23*2 = 46


3) Second bounce => rising   23/2 yards and falling the same => 11.5*2 = 23

 
4) Third bounce => rising 11.5/2 yards and falling the same => 5.75 * 2 = 11.5


5) Fourth bounce => rising 5.75 / 2  yards = 2.875


Sum = 46 + 46 + 23 + 11.5 + 2.875 = 129.375


Answer: 129.375 yd
5 0
3 years ago
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