I can’t see where they are
1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7
1*n-((5/6)*n)+(1/3)*n-10+7 = 0
n+(-5/6)*n+(1/3)*n-10+7 = 0
1/2*n-3 = 0 // + 3
1/2*n = 3 // : 1/2
n = 3/1/2
n = 6
That's just in case you had to show your work lol^^
Answer:

Step-by-step explanation:
Given:
Fifth term of a geometric sequence = 
Common ratio (r) = ¼
Required:
Formula for the nth term of the geometric sequence
Solution:
Step 1: find the first term of the sequence
Formula for nth term of a geometric sequence =
, where:
a = first term
r = common ratio = ¼
Thus, we are given the 5th term to be ¹/16, so n here = 5.
Input all these values into the formula to find a, the first term.




Cross multiply

Divide both sides by 16



Step 2: input the value of a and r to find the nth term formula of the sequence
nth term = 
nth term = 


- Expand & simplify ⇨
. Give your answer in the form
where b & c are integers.


Use binomial theorem
to expand
.

The square of
is 10.

Factor
. Rewrite the square root of the product
as the product of square roots
.

Multiply
and
to get 2.

Multiply -2 and 2 to get -4.

The square of
is 2.

Add 10 and 2 to get 12.

- Here, b & c are integers where

1) Initial fall => 46 yards
2) First bounce = > rising 46/2 yards and falling the same => 23*2 = 46
3) Second bounce => rising 23/2 yards and falling the same => 11.5*2 = 23
4) Third bounce => rising 11.5/2 yards and falling the same => 5.75 * 2 = 11.5
5) Fourth bounce => rising 5.75 / 2 yards = 2.875
Sum = 46 + 46 + 23 + 11.5 + 2.875 = 129.375
Answer: 129.375 yd