Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Use distance formula
=√(3-3)^2 +(-4-4)^2
=√64
=8
Step-by-step explanation:
1 -5/8
lcm=8
8-5=3
3/8
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Answer:
RS 3127.166
RS 107.834
Step-by-step explanation:
6 month bill :
Drawn date = Feb, 3
Discounted date = March 3,
Difference = 1 month
6 month - 1 month = 5 months = 5 * 30 = 150 days
Value of the bill :
P(1 - rate * time)
3235(1 - 0.08 * 150/360)
3235(1 - 0.08 * 0.4166666)
3235(1 - 0.0333333)
3235(0.9666666)
= Rs3127.1666
Value of bill = 3127.166
Bankers gain = 3235 - 3127.166 = 107.834
