Answer:
42=2×15+12
Step-by-step explanation:
2×15=30
therefore 30+12=42
Since 30 times 5= 150, he worked 150 hours for the rest of the week.
The desired measures for the data-set is given by:
<h3>How to find the five number summary and interquartile range of the data-set?</h3>
The five number summary is composed by the measures explained below, except the IQR.
- The minimum value is the smallest value from the data-set, as the maximum value is the greatest value of the data-set.
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference of the third quartile and the first quartile.
In this problem, we have that:
- The minimum value is the smallest value, of 48.
- The maximum value is the smallest value, of 80.
- The data-set has even cardinality, hence the median is the mean of the middle elements, which are 63 and 64, hence the median is of 63.5.
- The first quartile is the median of the five elements of the first half, hence it is of 54.
- The third quartile is the median of the five elements of the second half, hence it is of 74.
- The IQR is the difference between the quartiles, hence 74 - 54 = 20.
More can be learned about five number summaries at brainly.com/question/17110151
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Answer:
x = 32
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x+18) * 18 = 30^2
(x+18) * 18 = 900
Divide each side by 18
(x+18) * 18/18 = 900/18
(x+18) = 50
Subtract 18 from each side
x+18-18 = 50-18
x=32
