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Hitman42 [59]
3 years ago
13

How many tons are in 7,000 pounds

Mathematics
2 answers:
Genrish500 [490]3 years ago
4 0
2,000 pounds is one ton. So 7000/2000 = 3.5 tons.

3.5 tons = 7,000 pounds.
jok3333 [9.3K]3 years ago
3 0
1 <span>ton is 2204.623 pounds
</span><span>So, 7000/2204.623 = 3.175 tons

</span>
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A store manager orders T-shirts that 15 out of every 35 or medium. How many medium T-shirts would you expect to find when there
sladkih [1.3K]

There would be 60 medium shirts

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3 years ago
Suppose X has a continuous uniform distribution over the interval [1.3, 6.2]. Round your answers to 3 decimal places.
goldenfox [79]

Answer:

(a) 3.75

(b) 2.00083

(c) 0.4898

Step-by-step explanation:

It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].

(a)

Compute the mean of X as follows:

\mu_{X}=\frac{a+b}{2}=\frac{1.3+6.2}{2}=3.75

(b)

Compute the variance of X as follows:

\sigm^{2}_{X}=\frac{(b-a)^{2}}{12}=\frac{(6.2-1.3)^{2}}{12}=2.00083

(c)

Compute the value of P(X < 3.7) as follows:

P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898

Thus, the value of P(X < 3.7)  is 0.4898.

5 0
3 years ago
The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the
liberstina [14]

Answer:

<u>188 children</u> and <u>145 adults</u> were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

<u><em>Let the number of children admitted be </em></u>x.<u><em /></u>

<u><em>And the the number of adults admitted be </em></u>y.<u><em /></u>

So, the total people enter the park:

x+y=333\\\\x=333-y\ \ \ ...(1)

Thus, the total amount collected of the admission fee:

1.50(x)+4(y)=862\\\\

Substituting the value of x from equation (1):

1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.

<u><em>Thus, the number of adults = 145.</em></u>

Now, to get the number of children by substituting the value of y in equation (1) we get:

x=333-y\\\\x=333-145\\\\x=188.

<u><em>Hence, the number of children = 188.</em></u>

Therefore, 188 children and 145 adults were admitted in the park.

4 0
4 years ago
In which quadrant is the point (4, -5)?
oksian1 [2.3K]

Answer:

quadrant four (IV)

Step-by-step explanation:

hope this helps

5 0
3 years ago
Pleeeeeseee have to finish before 3:00
aleksley [76]

Answer:

175.9

Step-by-step explanation:

AL=2πrh=2·π·4·7≈175.92919 rounded to the nearest tenth would be 175.9

5 0
3 years ago
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